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*[NaX] = 0,1 M
*α = 10% = 0,1
*Kh ?
NaX ⇔ Na+ + X- ; maka yang terhidrolisis hanya konjugasi anion:
0,1 0,1 0,1
X- + H2O ⇒ HX + OH-
[OH-] = α x M
= 0,1 x 0,1
= 10^-2
Karena diket hanya garam, maka memakai rumus hidrolisis basa:
[OH-] = √Kh x M
10^-2 = √Kh x 0,1
Kh = 10^-3