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M NaOH= 1M+0,1M=1,1M
Vol HCl=20mL
M HCl=0,5 M
pH campuran?
NaOH + HCl ⇒ NaCl+H2O
m: 55mmol 10mmol
r: -10mmol -10mmol +10mmol
s: 45mmol - 10mmol
(OH-)=kb.b/g = 10^-5 . 45/10 = 10^-5 . 4,5 = 45.10^-4
POH=-log 45.10^-4 =4-log 45
pH= 14 - 4-log 45= 14-2,3 = 11,7