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pOH = 14 - pH
pOH = 14 - (11 + log 3)
pOH = 3 - log 3
[OH⁻] = 3 x 10⁻³
Rumus basa kuat :
[OH⁻] = M x Valensi
3 x 10⁻³ = M x 1
M = 3 x 10⁻³ M
mol = M x Volume
mol = 3 x 10⁻³ x 2
mol = 6 x 10⁻³ mol
Jadi, jumlah mol KOH adalah 6 x 10⁻³ mol