Question

Larutan Jenuh Ba(OH)2 mempunyai pH = 10, Tentukan Ksp Ba(OH)2 ?

Answer 1

Diket:
pH= 10
pOH= 4
[OH-]= 10^-4
Ba(OH)2 > Ba2+ + 2OH-
5x10^-5 10^-4

Ksp Ba(OH)2 = [Ba]2+ . [2OH-]^2
5x10^-5 . [2x10^-4]^2
Ksp Ba(OH)2= 2x10^-12