Larutan hno2 0,2M memiliki ph =2. Jika 500ml larutan NaNO2 memilik ph =8 log 2. Tentukan massa KNO2 Mr =85 yang terlarut
fatihahalhusna
![\text{\underline{Menentukan nilai Ka:}}\\pH=2\rightarrow [H^+]=10^{-2}\ M\\{[H^+]}=\sqrt{K_a.M}\\10^{-2}=\sqrt{K_a\times0,2}~~~(kuadratkan)\\10^{-4}=0,2K_a\\K_a=5\times10^{-4}](https://tex.z-dn.net/?f=%5Ctext%7B%5Cunderline%7BMenentukan+nilai+Ka%3A%7D%7D%5C%5CpH%3D2%5Crightarrow+%5BH%5E%2B%5D%3D10%5E%7B-2%7D%5C+M%5C%5C%7B%5BH%5E%2B%5D%7D%3D%5Csqrt%7BK_a.M%7D%5C%5C10%5E%7B-2%7D%3D%5Csqrt%7BK_a%5Ctimes0%2C2%7D%7E%7E%7E%28kuadratkan%29%5C%5C10%5E%7B-4%7D%3D0%2C2K_a%5C%5CK_a%3D5%5Ctimes10%5E%7B-4%7D "\text{\underline{Menentukan nilai Ka:}}\\pH=2\rightarrow [H^+]=10^{-2}\ M\\{[H^+]}=\sqrt{K_a.M}\\10^{-2}=\sqrt{K_a\times0,2}~~~(kuadratkan)\\10^{-4}=0,2K_a\\K_a=5\times10^{-4}")
![\text{\underline{Menentukan konsentrais [G]}}\\pH=8+\log2\rightarrow pOH=6-\log2\rightarrow [OH^-]=2\times10^{-6}\ M\\\\{OH^-}=\sqrt{\dfrac{K_w.[G]}{K_a}}\\\\2\times10^{-6}=\sqrt{\dfrac{10^{-14}[G]}{5\times10^{-4}}}~~~~~(kuadratkan)\\\\4\times10^{-12}=2\times10^{-11}[G]\\{[G]}=0,2\ M](https://tex.z-dn.net/?f=%5Ctext%7B%5Cunderline%7BMenentukan+konsentrais+%5BG%5D%7D%7D%5C%5CpH%3D8%2B%5Clog2%5Crightarrow+pOH%3D6-%5Clog2%5Crightarrow+%5BOH%5E-%5D%3D2%5Ctimes10%5E%7B-6%7D%5C+M%5C%5C%5C%5C%7BOH%5E-%7D%3D%5Csqrt%7B%5Cdfrac%7BK_w.%5BG%5D%7D%7BK_a%7D%7D%5C%5C%5C%5C2%5Ctimes10%5E%7B-6%7D%3D%5Csqrt%7B%5Cdfrac%7B10%5E%7B-14%7D%5BG%5D%7D%7B5%5Ctimes10%5E%7B-4%7D%7D%7D%7E%7E%7E%7E%7E%28kuadratkan%29%5C%5C%5C%5C4%5Ctimes10%5E%7B-12%7D%3D2%5Ctimes10%5E%7B-11%7D%5BG%5D%5C%5C%7B%5BG%5D%7D%3D0%2C2%5C+M "\text{\underline{Menentukan konsentrais [G]}}\\pH=8+\log2\rightarrow pOH=6-\log2\rightarrow [OH^-]=2\times10^{-6}\ M\\\\{OH^-}=\sqrt{\dfrac{K_w.[G]}{K_a}}\\\\2\times10^{-6}=\sqrt{\dfrac{10^{-14}[G]}{5\times10^{-4}}}~~~~~(kuadratkan)\\\\4\times10^{-12}=2\times10^{-11}[G]\\{[G]}=0,2\ M")
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