Question

Larutan HCl 0,1 M sebanyak 200ml mempunyai ph sebesar

Answer 1

Dik: M HCL=0,1 M
V HCL=200 ml=0,2 L
Dit: ph...?
jwb
[H+]= 1 × 0,1= 0,1=10 pngkt -1
ph= -log H+= -log 10 pngkt -1=1-log 1

Answer 2

HCL → H+ + Cl-
[H+] = x.[HA] = 1 . 0,1 M = 0,1
pH = – log [H+]
pH = – log 0,1
pH = 1

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