Question

Larutan H2SO4 mempunyai pH=2 - log4. hitung konsentrasi larutan asam sulfat tersebut

Answer 1

PH = 2 - log 4
-log [H+] = 2 - log 4
[H+] = 4 x 10^(-2) M

[H+] = M x a
4 x 10^(-2) M = M x 1
M (konsentrasi larutan) = 4 x 10^(-2) M
                                  = 0.04 M

Answer 2

PH = 2 - log 4
[H+] = 4 x10 ^-2
[H+] = x [H2SO4]
4 x 10^-2 = 2 [H2SO4]
[H2SO4] = 4 x10^-2 /2
[H2SO4] = 2 x 10 6-2 M = 0,02 M
jadi konsentrasi asam sulfat adalah 0,02 M