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NH4Cl (aq) --> NH4^+ (aq) + Cl^- (aq)
[H^+] = akar dari Kw/Kb x M
= akar dari 1 x 10^-14/1,8x10^5 x 0,72
= akar dari 0,4 x 10^-9
= akar dari 4 x 10^-10
= 2 x 10^-5
pH = -log[H^+]
= -log 2 x 10^-5
= 5 - log 2
Jawabannya adalah A