Question

Larutan Ch3COONa punya PH = 10, Ka CH³COOH = 10¯5 , konsentrasi CH³COONa adalah? jawab yaa, pusing kalii, pake cara yaa biar aku bisa dpt referensi utk ngerjai soal sejenis yg lain

Answer 1

Dik : pH CH₃COONa = 10 --> pOH = 4
        [OH⁻] = 10⁻⁴ M
        Ka = 10⁻⁵
Dit : [CH₃COONa] = .....?
Jwb: Hidrolisis
       [OH⁻]² = (Kw/Ka) x [CH₃COONa]
       (10⁻⁵)² = (10⁻¹⁴/10⁻⁵) x [CH₃COONa]
       10⁻¹⁰ = 10⁻⁹ [CH₃COONa]
       [CH₃COONa] = 10⁻¹ M
                            = 0,1 M