[H⁺] = ∝ × M
[H⁺] = 0,04 × 0,5
[H⁺] = 0,02 = 2.10^-2
Dilakukan pengenceran sebanyak 40 kali:
[H⁺] × V1 = [H⁺] × V2
2.10^-2 × 1 = [H⁺] × 40
[H⁺] =
[H⁺] = 5.10^-4
pH = -log[H⁺]
pH = 4 - log5
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
[H⁺] = ∝ × M
[H⁺] = 0,04 × 0,5
[H⁺] = 0,02 = 2.10^-2
Dilakukan pengenceran sebanyak 40 kali:
[H⁺] × V1 = [H⁺] × V2
2.10^-2 × 1 = [H⁺] × 40
[H⁺] =
[H⁺] = 5.10^-4
pH = -log[H⁺]
pH = 4 - log5