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cari Mr HCl dulu = 1+35,5=36,5
%HCl = 20,1% berat
massa jenis (p) = 1,015 gr/ml
n = mol
Ditanya : Konsentrasi dalam mol/L ?
Jawab :
%HCl = 20,1% = 20,1 gr HCl / 100 gr larutan
Volume larutan :
= m / p
= 100 gram / 1,015 gram/ml
= 98,52 ml
= 0,09852 L
Mr HCl :
= Ar H + Ar Cl
= 1 + 35,5
= 36,5 gr/mol
n HCl :
= m / Mr
= 20,1 gr / 36,5 gr/mol
= 0,551 mol
Konsentrasi HCl :
= n / V
= 0,551 mol / 0,09852 L
= 5,59 mol/L