LA SUMA DE TRES NUMEROS PARES CONSECUTIVOS RESTADOS EN 12 ES 36. HALLA EL NUMERO INTERMEDIO
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x
x+2
x+4
entonces:
(x+x+2+x+4)-12=36
(x+x+x+2+4)-12=36
(3x+6)-12=36
3x+6=36+12
3x+6=48
3x=48-6
3x=42
x=42/3
x=14
x=14
x+2..................14+2=16
x+4..................14+4=18
los numeros son:
14, 16 y 18
el intermedio es el numero 16