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r+t = 55 ec. 1
r = t+9 ec. 2
Sustituyendo valores de la ec. 2 en la ec. 1:
(t+9) + t = 55
2t + 9 = 55
2t = 55-9
2t = 46
t = 46/2
t = 23
De la ec. 1:
r+t = 55
r+23 = 55
r = 55-23
r = 32
Los dos números son:
32 y 23
Entre ellos hay una diferencia de 9 unidades y entre ellos suman 55.
Saludos....
x=y-9
y-9+y=55
2y=64
y=32
x=32-9
x=23