La suma de 7 números consecutivos es 3206. ¿Cuál es el número mayor?
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x + x+1 + x+2 + x+3 + x+4 + x+5 + x+6 = 3206
7x + 21 = 3206
7x = 3185
x = 455
Comprobamos:
455+(455+1)+(455+2)+(455+3)+(455+4)+(455+5)+(455+6) = 3206
455 + 456 + 457 + 458 + 459 + 460 + 461 = 3206
3206 = 3206
El número mayor es 461
Ojalá ayude
Saludos (^～^;)ゞ