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2do:x+1
3er:x+2 ..........(intermedio)
4to:x+3
5to:x+4
x+x+1+x+2+x+3+x+4=7x
5x+10=7x
10=2x
5=x
intermedio=x+2...........=5+2=7
RPTA: el intermedio es 7
1o. x ← menor
2o. x+1
3o. x+2 ← intermedio
4o. x+3
5o. x+4
x+(x+1)+(x+2)+(x+3)+(x+4)= 7x
5x+10= 7x
10= 7x-5x
10= 2x
x= 10/2
x= 5
Número intermedió: x+2
x+2= 5+2= 7
R. El número intermedio es 7
Comprobación:
x+(x+1)+(x+2)+(x+3)+(x+4)= 7x
5+(5+1)+(5+2)+(5+3)+(5+4)= 7(5)
5+6+7+8+9= 35
35= 35