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( x+2)( x-3)=6
x² - 3x + 2x - 6 = 6
x² - x - 6 = 6
x² - x - 6 - 6 = 0
x² - x - 12 = 0
x₁ = - (- 1) + √((1)² - 4 (- 12))/2
x₁ = 1 + √(1 + 48)/2
x₁ = 1 + √49/2
x₁ = (1 + 7)/2
x₁ = 8/2
x₁ = 4
x₂ = (1 - 7)/2
x₂ = - 6/2
x₂ = - 3
Respuesta.
Opción d)