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Donde: X1 = 3; Y1 = -2; X2 = 4; Y2 = 0
[(X - 3)]/[(4 - 3)] = [(Y - (-2))]/[(0 - (-2))]
[(X - 3)]/[(1)] = [(Y + 2)]/[(2)]
2(X - 3) = (Y + 2)
2X - 6 = Y + 2
Y = 2X - 8
Falso la ecuacion es Y = 2X - 8