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el anterior es x-1
el consecutivo es x + 1
(x-1) / 2 - 2 = (x + 1) / 3
x - 1 - 4 x + 1
----------- = ------------ multiplicando en aspa
2 3
3 (x - 5) = 2 (x+1)
3x - 15 = 2x + 2
3x - 2x = 2 + 15
x = 17