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El angulo = x
El complemento = 90° - x
Dos angulos son suplementarios cuando la suma de sus medias = 180°
El angulo = x
Suplemento = 180° - x
x - (90° - x) = ( 180 - x)/4
x - 90° + x = (180° - x)/4
2x - 90° = (180° - x)/4
4(2x - 90°) = 180° -x
8x - 360° = 180° - x
8x + x= 360° + 180°
9x =540°
x = 540° /9
x = 60°
El angulo mide 60°