Question

¿la diagonal menor de un rombo,si su diagonal mayor mide 4 cm y de lado 2.3cm?

Answer 1

Respuesta:

Explicación paso a paso:

[tex]Diagonal-mayor: AC= 4 cm[/tex]

[tex]Diagonal-menor: BD = ?[/tex]

[tex]Lado: AB = 2.3cm[/tex]

Por Pitágoras:

[tex](AB)^{2} = (EB)^{2} + (AE)^{2}[/tex]

[tex](2.3)^{2} = (\frac{BD}{2} )^{2} +(\frac{4}{2} )^{2}[/tex]

[tex]5.29 = \frac{(BD)^{2} }{4} + 4[/tex]

[tex]5.29-4 = \frac{(BD)^{2} }{4}[/tex]

[tex]1.29 =\frac{(BD)^{2} }{4}[/tex]

[tex](4)(1.29) = (BD)^{2}[/tex]

[tex]5.16 = ( BD)^{2}[/tex]

[tex]\sqrt{5.16} = BD[/tex]

[tex]2.27 cm = BD[/tex]

Respuesta:

     [tex]2.27cm[/tex]