La base de un triangulo es 8 metro mayor que la altura ;el area mide 42m² ¿cuanto mide la base y la altura
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b = base
a = b + 8
A = 42 m²
A = (1/2)ab
(1/2)ab=42
b(b+8) = 84
b² + 8b - 64 = 0
b = -4+4√5
a = 8 - 4 + 4√5
a = 4 + 4√5