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Kimia XI
Diketahui
Kelarutan Ag₃PO₄ = x mol/liter
Ditanya
Hasilkali kelarutan (Ksp)
Penyelesaian
Reaksi ionisasi
Ag₃PO₄ ⇄ 3 Ag⁺ + PO₄³⁻
__x_______3x____x
⇔ Ksp = [Ag⁺]³. [PO₄³⁻]
⇔ Ksp = [3x]³. [ x ]
⇔ Ksp = 27x⁴
Jadi hasilkali kelarutan Ag₃PO₄ adalah 27x⁴