D=m/v m=Dv m=2.51g/L x (22.4L) = 56.224 g
FE: CH2
C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
`````````````````````````````
Mm FE = 14 g/mol
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D=m/v
m=Dv
m=2.51g/L x (22.4L) = 56.224 g
FE: CH2
C: 1 x 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
`````````````````````````````
Mm FE = 14 g/mol
n = 56.224 g/mol
````````````````````
14 g/mol
n = 4
FE = (FM)n
FM = (CH2)4 = C2H8
respuesta d