Question

7)
[OH-] = 0,001 mol-ion/l. jakie będzie pH?

Answer 1

proszę :)

Answer 2

[OH⁻]=10⁻³
[H⁺][OH⁻]=10⁻¹⁴
[H⁺] = 10⁻¹⁴ / [OH⁻]
[H⁺] = 10⁻¹⁴ / 10⁻³
[H⁺] = 10⁻¹¹
pH=-log[H⁺]
pH = 11