Question

Kx^2-(2k-1) x+(k+6)=0
Tentukan K sehingga memiliki akar2 kembar!

Answer 1

Verified answer

Jawab

kx² -(2k -1)x  + (k+6)= 0
a = k
b = -(2k -1) = (1 - 2k)
c = k + 6

syarat memiliki akar kembar  D =0, k ≠ 0
b² - 4ac = 0
(1 - 2k)²- 4(k)(k+6) = 0
1 - 4k + 4k² - 4k² - 24k = 0
1- 28 k = 0
k = 1/28