Question

Kuis ⁽¹⁹⁶⁾ :
p³ = 3p² + 4p - 12
p = {...., ....., .....}

Answer 1

Penjelasan dengan langkah-langkah:

AljAbar

p³ = 3p² + 4p - 12

p³ - 3p² - 4p + 12 = 0

p²(p-3) -4(p-3) = 0

(p²-4)(p-3) = 0

p² - 4 = 0

p² = 4

p = √4

p = ±2

p - 3 = 0

p = 3

p = { -2 , 2 , 3 }