Question

Kuis ₍₁₀₁₎ :
³ log ( 7 + ⁴ log ( 13 + ² log ( a + 4 ) ) ) = 2

Nilai a = ..........................................................

Answer 1

Penjelasan dengan langkah-langkah:

³log (7+⁴log(13+²log (a+4)) = 2

2 adalah hasil ³log 9

³log (7+⁴log(13+²log(a+4)) = ³log 9

eleminasi ³log

7+⁴log(13+²log(a+4)) = 9

⁴log(13+²log(a+4)) = 9-7

⁴log(13+²log(a+4)) = 2

2 adalah hasil ⁴log 16

⁴log(13+²log(a+4)) = ⁴log 16

eleminasi ⁴log

13+²log(a+4) = 16

²log (a+4) = 16-13

²log (a+4) = 3

3 adalah hasil ²log 8

²log (a+4) = ²log 8

eleminasi ²log

a+4 = 8

a = 8-4

a = 4

maka nilai a adalah 4 ,

empat , four , arbaatun

:v

Answer 2

Verified answer

³log(7 + ⁴log(13 + ²log(a + 4))) = 2

Menggunakan sifat logaritma:

ᵃlogaˣ = x

7 + ⁴log(13 + ²log(a + 4)) = 3²

⁴log(13 + ²log(a + 4)) = 9 - 7

⁴log(13 + ²log(a + 4)) = 2

13 + ²log(a + 4) = 4²

²log(a + 4) = 16 - 13

²log(a + 4) = 3

a + 4 = 2³

a = 8 - 4

a = 4

Jadi, nilai a sama dengan 4.