mCu(NO3)2=63,5u+2*14u+6*16u=187,5u
96u---x%
187,5u---100%
x=51,2%O
mCuSO4=63,5u+32u+4*16u=159,5u
64u---x%
159,5u---100%
x=40,13%O
Odp: Więcej tlenu jest w Cu(NO3)2
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mCu(NO3)2=63,5u+2*14u+6*16u=187,5u
96u---x%
187,5u---100%
x=51,2%O
mCuSO4=63,5u+32u+4*16u=159,5u
64u---x%
159,5u---100%
x=40,13%O
Odp: Więcej tlenu jest w Cu(NO3)2