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P2=40W
U=230V
R1=?
R2=?
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P=U*I ale I=U/R stąd P=U²/R
R=U²/P
R1=U²/P1=230²/100=529Ω
R2=U²/P2=230²/40=1322,5Ω
żarówka 100W ma mniejszy opór elektryczny