Odpowiedź:
Trapez ABCD
Niech
a = 10
α = 30°
x = [tex]\frac{10 - b}{2}[/tex]
oraz [tex]\frac{x}{b} = \frac{10 - b }{2 b} = cos 30^o = \frac{\sqrt{3} }{2}[/tex]
2 √3 b = 20 - 2 b / : 2
√3 b = 10 - b
√3 b - b = 10
( √3 - 1 )*b = 10
b = [tex]\frac{10}{\sqrt{3}- 1 }[/tex]
Obwód
L = 10 + 3 b = 10 + [tex]\frac{30}{\sqrt{3} - 1 }[/tex]
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Verified answer
Odpowiedź:
Trapez ABCD
Niech
a = 10
α = 30°
x = [tex]\frac{10 - b}{2}[/tex]
oraz [tex]\frac{x}{b} = \frac{10 - b }{2 b} = cos 30^o = \frac{\sqrt{3} }{2}[/tex]
2 √3 b = 20 - 2 b / : 2
√3 b = 10 - b
√3 b - b = 10
( √3 - 1 )*b = 10
b = [tex]\frac{10}{\sqrt{3}- 1 }[/tex]
Obwód
L = 10 + 3 b = 10 + [tex]\frac{30}{\sqrt{3} - 1 }[/tex]
Szczegółowe wyjaśnienie: