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Ar
Cu = 63,5
N = 14
O = 16
H = 1
Mr Cu(NO3)2 . x H2O
= 63,5 + (14 + 48)*2 + 18x
= 187,5 + 18x
36,54/100 * (187,5 + 18x) = 18x
68,5125 + 6,5772x = 18x
68,5125 = 11,4228x
x = 5,99 ~ 6
maka rumus senyawa hidrat tersebut
Cu(NO3)2 . 6H2O