Kotak persegi panjang tanpa tutup dibuat dari papan 12 m^2. Carilah volume maksimum kotak tersebut!
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s² = 12/5
s² = 2,4 m²
s² = 2,4 x 100²
s² = 24.000 dm²
s² = (1.600 x 15 )
s =√(1.600 x 15)
s = 40√15 dm
Volume maksimum
= s³
= (40√15)³
= 40³ x (√15)² x √15
= 64.000 x 15√15
= (960.000√15) liter