Question

Koordinat titik potong y=2x + 1 dan parabola y= x² - x+1

Answer 1

Y = 2x + 1 sub ke y = x² - x + 1

x² - x + 1 = 2x + 1
x² -x  - 2x + 1 -1 = 0
x² - 3x  = 0
x(x - 3)= 0
x = 0 atau x = 3

y = 2x + 1
untk x = 0 --> y = 2(0) + 1 = 1 --> titik A(x,y)=(0,1)
untk x = 3 --> y = 2(3) + 1 = 7 --> titi B(x,y)= (3,7)