Question

Koordinat titik fokus parabola x^2 + 4x + 8y + 12 = 0

Answer 1

(x+2)^2 = -8y -12 + 4
(x+2)^2 = - 8y - 8
(x-2)^2 = -8(y+1)
a= 2
b = -1
4p =-8
p =-2
Fokus { a, (b+p) } = F( 2, -3)