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Verified answer
F(x) = 2x² - 8x + 3koordinat titik balik fungsi f(x) adalah (-b/2a , f(-b/2a))
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-b/2a
= 8/(2 . 2)
= 8/4
= 2
f(-b/2a)
= f(2)
= 2(2)² - 8(2) + 3
= 8 - 16 + 3
= -5
jadi koordinat titik balik fungsi f adalah (2,-5)