Question

koordinat titik balik grafik fungsi kuadrat f(x) = ½ X² - 4x + 6 adalah....

mohon bantuannya ya kak.
ak kasi bintang 5 deh.
poin gede juga​

Answer 1

Verified answer

f(x) = ½x² - 4x + 6

a = ½, b = -4, c = 6

Koordinat titik balik:

[tex]\begin{aligned} \Rightarrow& \ \sf(x_p,y_p) \\ \Rightarrow&\sf \left(-\frac{b}{2a},-\frac{D}{4a}\right) \\ \Rightarrow&\sf \left(-\frac{b}{2a},-\frac{b^2 - 4ac}{4a}\right) \\ \Rightarrow&\sf \left(-\frac{(-4)}{2(^1\!/\!_2)},-\frac{(-4)^2 - 4(^1\!/\!_2)(6)}{4(^1\!/\!_2)}\right) \\ \Rightarrow&\sf \left(-\frac{(-4)}{1},-\frac{16 - 12}{2}\right) \\ \Rightarrow&\sf \left(-(-4),-\frac{4}{2}\right) \\ \Rightarrow& \ \sf (4,-2) \end{aligned}[/tex]

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