Question

Koordinat titik balik fungsi kuadrat: f{x}= 5+8x-4Xkuadrat adalah...

Answer 1

F(x) = -4x² + 8x + 5

x = -b/2a
x = -8/2(-4)
x = 1

y = f(1) = -4(1)² + 8(1) + 5
y = -4 + 8 + 5
y = 9

titik balik --> (1,9)

semoga membantu :)