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Kelas 10 MatematikaBab Koordinat Kutub
(-2, 2√3) → x negatif dan y positif, maka di Kuadran II
r = √(x² + y²)
r = √((-2)² + (2√3)²)
r = √(4 + 12)
r = √16
r = 4
tan a = y/x
tan a = (2√3)/(-2)
tan a = -√3
a = 120°
(4, 120°)