" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
T2 = y=-x --------> T2 = |0...-1||-1....0|
(x',y') = T2 oT1 |-2...3|
(x',y') = |-1/2√3...-1/2||-1/2...1/2√3|{-2...3}
(x'y') = |(√3 - 3/2), (1+3/2 √3)|
x' = √3 - 3/2
y' = 1 + 3/2 √3