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PbCrO₄ ⇆ Pb²⁺ + CrO₄²⁻
s s s
Ksp = [s] [s]
2,8 x 10⁻¹⁴ = s²
s = √2,8 x 10⁻¹⁴
s = 1,67 x 10⁻⁷
Jadi, konsentrasi Pb²⁺ adalah 1,67 x 10⁻⁷ M
Ok?
PbCrO₄ ⇆ Pb²⁺ + CrO₄²⁻
s s s
Ksp = [s] [s]
2,8 x 10⁻¹⁴ = s²
s = √2,8 x 10⁻¹⁴
s = 1,67 x 10⁻⁷
Jadi, konsentrasi Pb²⁺ adalah 1,67 x 10⁻⁷ M