Kalau luar sisi tegak itu sudah diketahui maka tidak perlu 3×luas
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[tex]\begin{aligned} LP &= 2 ( 1/2 × a × b )+ t(a + b + c) \\&= 2 ( 1/2 × 10 × 8 )+ 20(10 + 8 + 15) \\&= 2(40)+ 20(33) \\&= 80 + 660 \\&= \boxed{\bold{\underline{740~cm^2}}} \end{aligned}[/tex]
[tex]\begin{aligned} LP &= (a × b) + (a × t) + (b × t) + (c × t) \\&= (10 × 8) + (10 × 20) + (8×20)+(15×20) \\&= 80 + 200 + 160 + 300 \\&= 280 + 460 \\&= \boxed{\bold{\underline{740~cm^2}}} \end{aligned}[/tex]
[tex]\begin{array}{lr}\texttt{Care For Lupus}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 10 - 05 - 2023}}[/tex]
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Kalau luar sisi tegak itu sudah diketahui maka tidak perlu 3×luas
Bangun Ruang Sisi Tegak
[Prisma Segitiga Siku-Siku]
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Cara Pertama
[tex]\begin{aligned} LP &= 2 ( 1/2 × a × b )+ t(a + b + c) \\&= 2 ( 1/2 × 10 × 8 )+ 20(10 + 8 + 15) \\&= 2(40)+ 20(33) \\&= 80 + 660 \\&= \boxed{\bold{\underline{740~cm^2}}} \end{aligned}[/tex]
Cara Kedua
[tex]\begin{aligned} LP &= (a × b) + (a × t) + (b × t) + (c × t) \\&= (10 × 8) + (10 × 20) + (8×20)+(15×20) \\&= 80 + 200 + 160 + 300 \\&= 280 + 460 \\&= \boxed{\bold{\underline{740~cm^2}}} \end{aligned}[/tex]
[tex]\begin{array}{lr}\texttt{Care For Lupus}\end{array}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 10 - 05 - 2023}}[/tex]