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(COOH)2 + KMNO4 + H2SO4 = CO2 + MNSO4 + K2SO4 + H2O
Setarakan :
5 (COOH)2 + 2 KMnO4 + 3 H2SO4 = 10 CO2 + 2 MnSO4 + K2SO4 + 8 H2O
2MnO4- + 16H+ +10e --> 2Mn2+ + 2H2O (Reduksi)
5 (COOH)2 --> 10 CO2 + 10H+ + 10e (Oksidasi)
semoga membantu :)