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2b+3 - (c-5)= 9 -> 2b - c= 1 ...................................(2)
3c-1 - (a+3)= 12 -> 3c - a=16 .................................(3)
eliminasi (1) dan (3) diperoleh
a - b= -4
-a+ 3c=16
-b+3c=12 -> -2b+6c=24..........................................(4)
eliminasi (2) dan (4) diperoleh
2b - c =1
-2b+6c=24
5c=25
c=5 subtitusikan ke (2)
2b - 5=1
2b=6
b=3 substitusikan ke (1)
a - 3 = -4
a= -1
jadi nilai a= -1, b= 3, dan c= 5.