liliput01
Diket: lo = 10 cm t₁ = 25'c t₂ = 33'c Δt = t₂ - t₁ = 33 - 25 = 8'c α = 1,2 x 10⁻⁷/'c Dit: Δl dan l....? jawab: Δl = lo α Δt Δl = 10 x 1,2x10⁻⁷ x 8 Δl = 1,2x10⁻⁶ x 8 Δl = 9,6 x10⁻⁶ Δl = 0,0000096 cm , l = lo + Δl l = 10 + 0,0000096 l = 10,0000096 cm jawab A
lo = 10 cm
t₁ = 25'c
t₂ = 33'c
Δt = t₂ - t₁ = 33 - 25 = 8'c
α = 1,2 x 10⁻⁷/'c
Dit: Δl dan l....?
jawab:
Δl = lo α Δt
Δl = 10 x 1,2x10⁻⁷ x 8
Δl = 1,2x10⁻⁶ x 8
Δl = 9,6 x10⁻⁶
Δl = 0,0000096 cm
,
l = lo + Δl
l = 10 + 0,0000096
l = 10,0000096 cm
jawab A