Question

Kimia No 2,3,4 Pake Jalan Pliss

Answer 1

2. n FeS2 = 24 / 120 = 0.2 mol
n S dalam FeS2 = MrS2/MrFes2 x nFeS2 = 64/120 x 0.2 = 0.10 -B-
3. nO2 = 6.02 x 10pangkat23 / 6.02 x 10pangkat23 = 1 mol
Massa = n x Mr
Mr O2 =16
Massa = 1 x 16 = 16 gram -B-
4. Keadaan STP 1 mol gas = 22.4 liter
Maka, 0.5 x 22.4 = 11.2 liter -E-