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Q=c*m*deltaT
c-ciepło właściwe wody = 4200 J/kg°K
Q-ciepło dostarczane = 84000 J
m-masa ciała = 1 kg
deltaT-przyrost temperatury
Q = cmΔT
ΔT = Q/cm = 84000/4200 razy 1 = 84000/4200 = 20°C
odp
przyrośt temparatury wynosi 20°C
Q = c*m*ΔT
ΔT = Q/cm
ΔT =84000/4200 razy 1
ΔT =84000/4200
ΔT =20°C