ile energii odda otoczeniu sszklanka(0.25l) goracej wody(100 stopni) do chwili ostygniecia w pokoju, w którym temp wynosi 20 stopni. CIepło wlasciwe wody 4200 J/kgK a to 3 to jak
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m = 0,25 kg
t1 = 100 st C
t2 = 20 st C
c = 4 200 J/kgK
Q = m*c*[t1 - t2]
Q = 0,25 kg * 4 200 J/kgK * [ 100 - 20] K = 84 000 J
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