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Q2=m.Les=2.336000=672000
Q3=m.Cair.t=2.4200.20=168000
Q=Q1+Q2+Q3=420000+672000+168000=882000j=882kj
t₂ = 0°C
Δt₁ = 10°C
t₃ = 20°C
Δt₂ = 20°C
m = 2 kg
c es = 2.100 J/kg°C
L = 336.000 J/kg°C
c air = 4.200 J/kg°C
Dit : kalor yang dibutuhkan (Q) = .......?
Jwb : Q = Q₁ + Q₂ + Q₃
= m (c es Δt₁ + L + c air Δt₂)
= 2 ( 2.100 x 10 + 336.000 + 4.200 x 20)
= 2 ( 21.000 + 336.000 + 84.000)
= 2 (441.000)
= 882.000 J
= 882 KJ