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m= 2 kg
T1= 30°C
T2= 100°C
c= 4.200 J/Kg°C
ditanya
Q=...?
jawab
ΔT= T2-T1
= 100-30= 70°C
Q= m.c.ΔT
Q= 2 × 4.200 × 70
Q= 588.000 Joule→ 588 kJ