Question

1.Ibu merebus 2 kg air bersuhu 28°C hingga mendidih pada suhu 100°C.Apabila kalor jenis air 4.200 J/kg°C,kalor yg diperlukan sebesar

Answer 1

Dik = m = 2kg
t1 = 28°C
t2 = 100°C
Cair = 4.200 J/Kg°C
Dit = Q ?
Jawab = Q = m.c.Δt
= 2 x 4200 x (100-28)
= 8400 x 72
= 604.800 Joule

Answer 2

Q=mxcx▲t
=2kgx4.200 j/kg°c, x(100°c-28°c)
=8400j/°c x 72°c
=604.700 j